\(\begin{array}{l}
1)\\
XC{O_3} + 2HCl \to XC{l_2} + C{O_2} + {H_2}O\\
nC{O_2} = \dfrac{{4,48}}{{22,4}} = 0,2\,mol\\
nHCl = 2nC{O_2} = 0,4\,mol\\
n{H_2}O = nC{O_2} = 0,2\,mol\\
BTKL\\
mX + mHCl = m + mC{O_2} + m{H_2}O\\
\Rightarrow m = 17,6 + 0,4 \times 36,5 - 0,2 \times 44 - 0,2 \times 18 = 19,8g\\
2)\\
{X_2}C{O_3} + 2HCl \to 2XCl + C{O_2} + {H_2}O\\
nC{O_2} = \dfrac{{2,24}}{{22,4}} = 0,1\,mol\\
nHCl = 2nC{O_2} = 0,2\,mol\\
n{H_2}O = nC{O_2} = 0,1mol\\
BTKL\\
mX + mHCl = m + mC{O_2} + m{H_2}O\\
\Rightarrow m = 12,2 + 0,2 \times 36,5 - 0,1 \times 44 - 0,1 \times 18 = 13,3g
\end{array}\)