Giải thích các bước giải:
Do \(f\left( 3 \right) = 16\) nên \(f\left( 3 \right) = a{.3^2} = 16 \Rightarrow a.9 = 16 \Rightarrow a = \frac{{16}}{9}\)
Vậy \(y = f\left( x \right) = \frac{{16}}{9}{x^2}\)
\(\begin{array}{l}
f\left( 2 \right) = \frac{{16}}{9} \cdot {2^2} = \frac{{64}}{9};\\
f\left( { - 2} \right) = \frac{{16}}{9} \cdot {\left( { - 2} \right)^2} = \frac{{64}}{9};\\
f\left( 0 \right) = \frac{{16}}{9} \cdot {0^2} = 0;\\
f\left( 1 \right) = \frac{{16}}{9} \cdot {1^2} = \frac{{16}}{9};\\
f\left( { - 1} \right) = \frac{{16}}{9}.{\left( { - 1} \right)^2} = \frac{{16}}{9}
\end{array}\)
