A.\(\dfrac{{x - 4}}{{ - 3}} = \dfrac{{y + 3}}{2} = \dfrac{{z - 2}}{1}\)
B.\(\left\{ \begin{array}{l}x = 1 - 3t\\y = - 1 + 2t\\z = 3 + t\end{array} \right.\)
C.\(\dfrac{{x - 1}}{{ - 2}} = \dfrac{{y + 1}}{1} = \dfrac{{z - 3}}{4}\)
D.\(\dfrac{{x + 2}}{1} = \dfrac{{y - 1}}{{ - 1}} = \dfrac{{z - 4}}{3}\)
Loga
Hóa Học lớp 12
