Đáp án:
a. \(x=\frac{-2}{3}\)
b. \(x=1; x=\frac{-1}{2}\)
Giải thích các bước giải:
a. \(\frac{1-x}{x+1}-\frac{3+2x}{x+1}=0\) (*)
ĐK: \(x-1 \neq 0 \leftrightarrow x \neq -1\)
(*) \(\leftrightarrow \frac{1-x-3-2x}{x+1}=0\)
\(\leftrightarrow \frac{-2-3x}{x+1}=0\)
\(\leftrightarrow -2-3x=0 \leftrightarrow x=\frac{-2}{3}\)
b. \(1-\frac{x}{x+1}+3=2x+\frac{3}{x+1}\)
ĐK: \(x \neq -1\)
\(\leftrightarrow \frac{(x+1)-x+3(x+1)}{x+1}=\frac{2x(x+1)+3}{x+1}\)
\(\leftrightarrow 2x^{2}+2x+3=3x+4\)
\(\leftrightarrow 2x^{2}-x-1=0\)
\(\leftrightarrow x=1; x=\frac{-1}{2}\)
