`***`Lời giải`***`
`(x-1)(x-12)=(2x-3)(5x-4)`
`<=>x(x-12)-(x-12)=2x(5x-4)-3(5x-4)`
`<=>x^2-12x-x+12=10x^2-8x-15x+12`
`<=>x^2-10x^2-12x-x+15x+8x=12-12`
`<=>-9x^2+10x=0`
`<=>x(10-9x)=0`
`<=>`\(\left[ \begin{array}{l}x=0\\10-9x=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=0\\9x=10\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=0\\x=\dfrac{10}{9}\end{array} \right.\)
Vậy `S={0;10/9}`
