Đáp án:
$\\$
`(x-1)^2 = 1-x`
`-> (x-1)^2 - 1 + x=0`
`-> (x-1) (x-1) - 1 +x=0`
`-> x (x-1) -1 (x-1) - 1 +x=0`
`-> x^2 - x - x + 1 - 1+x=0`
`-> x^2 + (-x-x+x) + (1-1)=0`
`-> x^2 -x=0`
`-> x (x-1)=0`
`->` \(\left[ \begin{array}{l}x=0\\x-1=0\end{array} \right.\)
`->` \(\left[ \begin{array}{l}x=0\\x=1\end{array} \right.\)
Vậy `x=0` hoặc `x=1`