Gửi bạn ạ. Cho xin 5*và ctlhn có đc ko ạ.
ĐặtA=1+2+22+...+299;B=(1+2+22+23+...+299)−2100A=1+2+22+...+299;B=(1+2+22+23+...+299)-2100
2A=2+22+23+...+21002A=2+22+23+...+2100
2A−A=(2+22+23+...+2100)−(1+2+22+...+299)2A-A=(2+22+23+...+2100)-(1+2+22+...+299)
A=2100−1A=2100-1
⇒B=A−1⇒B=A-1
=2100−1−2100=2100-1-2100
=−1=-1