`|x-1/2| - 7 =-3`
`=> |x-1/2| = -3 +7`
`=> |x-1/2| =4`
`=>` \(\left[ \begin{array}{l}x- \dfrac{1}{2}=4 \\x - \dfrac{1}{2} =-4\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=\dfrac{9}{2}\\x=\dfrac{-7}{2}\end{array} \right.\)
Vậy `x \in {9/2 ; -7/2}`