Đáp án:
$x = \dfrac{{37}}{4};y = \dfrac{{83}}{8}z = \dfrac{{39}}{2}$
Giải thích các bước giải:
Ta có:
$\begin{array}{l}
\dfrac{{x - 1}}{2} = \dfrac{{y + 2}}{3} = \dfrac{{z - 3}}{4}\\
\Rightarrow \dfrac{{x - 1}}{2} = \dfrac{{y + 2}}{3} = \dfrac{{z - 3}}{4} = \dfrac{{x - 2\left( {y + 2} \right) + 3\left( {z - 3} \right)}}{{2 - 2.3 + 3.4}} = \dfrac{{x - 2y + 3z - 13}}{8} = \dfrac{{46 - 13}}{8} = \dfrac{{33}}{8}\\
\Rightarrow \left\{ \begin{array}{l}
\dfrac{{x - 1}}{2} = \dfrac{{33}}{8} \Rightarrow x = \dfrac{{37}}{4}\\
\dfrac{{y + 2}}{3} = \dfrac{{33}}{8} \Rightarrow y = \dfrac{{83}}{8}\\
\dfrac{{z - 3}}{4} = \dfrac{{33}}{8} \Rightarrow z = \dfrac{{39}}{2}
\end{array} \right.
\end{array}$
$ \Rightarrow x = \dfrac{{37}}{4};y = \dfrac{{83}}{8}z = \dfrac{{39}}{2}$
Vậy $x = \dfrac{{37}}{4};y = \dfrac{{83}}{8}z = \dfrac{{39}}{2}$
