`~rai~`
$\begin{array}{1}(x+1)^3-(x-1)^3-6(x-1)^2=-10\\\Leftrightarrow x^3+3x^2+3x+1-(x^3-3x^2+3x-1)-6(x^2-2x+1)=-10\\\Leftrightarrow x^3+3x^2+3x+1-x^3+3x^2-3x+1-6x^2+12x-6=-10\\\Leftrightarrow 12x-4=-10\\\Leftrightarrow 12x=-6\\\Leftrightarrow x=-0,5.\\\text{Vậy x=-0,5.} \end{array}$