`(x - 1/3)^100 = (2^17 + 17^2) . (9^15 - 3^15) . (2^4 - 4^2)`
`text(Ta có :)`
`(2^17 + 17^2) . (9^15 - 3^15) . (2^4 - 4^2)`
`= (2^17 + 17^2) . (9^15 - 3^15) . (16 - 16)`
`= (2^17 + 17^2) . (9^15 - 3^15) . 0`
`= 0`
`⇒ (x - 1/3)^100 = 0`
`⇒ x - 1/3 = 0`
`⇒ x = 1/3`