a) $\dfrac{1}{4}+x=\dfrac{5}{2}×\dfrac{8}{7}$
$⇔ x=\dfrac{20}{7}-\dfrac{1}{4}=\dfrac{73}{28}$
b) $\dfrac{7}{3}-x=\dfrac{11}{5}:\dfrac{5}{6}$
$⇔ x=\dfrac{7}{3}-\dfrac{66}{25}=-\dfrac{23}{75}$
c) $x+\dfrac{5}{2}×\dfrac{2}{3}=\dfrac{5}{2}$
$⇔ x=\dfrac{5}{2}-\dfrac{5}{3}=\dfrac{5}{6}$
d) $\dfrac{23}{6}:x-\dfrac{2}{5}=\dfrac{1}{4}$
$⇔ \dfrac{23}{6}:x=\dfrac{13}{20}$
$⇔ x=\dfrac{23}{6}:\dfrac{13}{20}=\dfrac{230}{39}$