\(\left( {\frac{1}{{x + 4}} + \frac{8}{{{x^2} - 16}}} \right):\frac{{x + 1}}{{x - 4}}\,\,\) \(\left( {x \ne  \pm 4;\,\,x \ne  - 1} \right).\)
A.\(\frac{x-4}{{x + 4}}\)
B.\(\frac{1}{{x - 1}}\)
C.\(\frac{1}{{x + 1}}\)
D.\(\frac{1}{{x + 4}}\)

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