\(\begin{array}{l}
a)\,\,\left| {x - 1,5} \right| + \left| {2,5 - x} \right| = 0\\
\Leftrightarrow \left\{ \begin{array}{l}
\,\left| {x - 1,5} \right| = 0\\
\,\left| {x - 2,5} \right| = 0
\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}
x - 1,5 = 0\\
x - 2,5 = 0
\end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}
x = 1,5\\
x = 2,5
\end{array} \right.
\end{array}\)
Suy ra không có giá trị nào của \(x\) thỏa mãn yêu cầu bài toán.
\(\begin{array}{l}
b)\,\,\left| {x + \dfrac{1}{3}} \right| - 4 = - 1\\
\Leftrightarrow \,\left| {x + \dfrac{1}{3}} \right| = - 1 + 4\\
\Leftrightarrow \,\left| {x + \dfrac{1}{3}} \right| = 3\\
\Leftrightarrow \left[ \begin{array}{l}
x + \dfrac{1}{3} = 3\\
x + \dfrac{1}{3} = - 3
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = 3 - \dfrac{1}{3}\\
x = - 3 - \dfrac{1}{3}
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = \dfrac{8}{3}\\
x = \dfrac{{ - 10}}{3}
\end{array} \right.
\end{array}\)
Vậy \(\dfrac{8}{3}\) hoặc \(\dfrac{-10}{3}.\)
