Đáp án:
`x + |1 - x|= 5`
`⇔` \(\left[ \begin{array}{l}x + 1 - x = 5\\x -1 + x = 5\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}(x - x) + 1 = 5\\(x + x) - 1 = 5\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}0 = 4 (L)\\2x = 6\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}0=4 (L)\\x=3\end{array} \right.\)
`text{Vậy x = 3}`