Bài 1: Tìm x.
a) x + $\frac{5}{7}$ = $\frac{32}{9}$ - $\frac{-3}{4}$
x + $\frac{5}{7}$ = $\frac{155}{36}$
x = $\frac{155}{36}$ - $\frac{5}{7}$
x = $\frac{905}{252}$.
b) | x - $\frac{2}{5}$ | = $\frac{1}{3}$
⇒ x - $\frac{2}{5}$ = $\frac{1}{3}$
x = $\frac{1}{3}$ + $\frac{2}{5}$
x = $\frac{11}{15}$.
⇒ x - $\frac{2}{5}$ = $\frac{-1}{3}$
x = $\frac{-1}{3}$ + $\frac{2}{5}$
x = $\frac{1}{15}$.
Vậy x = $\frac{11}{15}$ hay x = $\frac{1}{15}$.
