a)
Phản ứng xảy ra:
\(Ca{C_2} + 2{H_2}O\xrightarrow{{}}Ca{(OH)_2} + {C_2}{H_2}\)
Ta có:
\({n_{{C_2}{H_2}}} = \frac{{6,72}}{{22,4}} = 0,3{\text{ mol = }}{{\text{n}}_{Ca{C_2}}}\)
\( \to {m_{Ca{C_2}}} = 0,3.(40 + 12.2) = 19,2{\text{ gam}}\)
b)
Phản ứng xảy ra:
\({C_2}{H_2} + 2B{r_2}\xrightarrow{{}}{C_2}{H_2}B{r_4}\)
Ta có:
\({n_{{C_2}{H_2}B{r_4}}} = \frac{{93,42}}{{12.2 + 80.4}} = 0,27{\text{ mol = }}{{\text{n}}_{{C_2}{H_2}{\text{ lt}}}}\)
\( \to {n_{{C_2}{H_2}{\text{ tham gia}}}} = \frac{{0,27}}{{90\% }} = 0,3{\text{ mol}}\)
\( \to m={m_{{C_2}{H_2}}} = 0,3.62 = 19,2{\text{ gam}}\)