1)
CuO + 2HCl ==> CuCl2 + H2O
0,1..........0,2.............0,2............................(mol)
nHCl= 0,1x2= 0,2 (mol)
==> mCuO= 0,1x80=8 (g)
==> mCu= 18-8=10 (g)
CuCl2 + 2NaOH ==> Cu(OH)2 + 2NaCl
0,2.......................................0,2
mCu(OH)2= 0,2 x 98= 19,6 (g)
2)
Fe + H2SO4 ==> FeSO4 + H2
0,15....0,15................0,15..................0,15...(mol)
nH2=3,36/22,4=0,15 (mol)
=> %mFe= ((0,15 x 56)/12) x 100= 70%
%mCu= 100-70=30%
Cu + 2AgNO3 ==> Cu(NO3)2 + 2Ag
0,05625....0,1125.........................................................(mol)
nCu= 3,6/64= 0,05625 (mol)
Ta có: C%=(mct/mdd)x100
==> mdd= (mct x 100)/C%= (0,1125 x 170 x 100)/2=956,25 (g)