Em tham khảo nha:
Em xem lại câu 2 có phải là 265g không nhé
\(\begin{array}{l}
1)\\
a)\\
CuO + 2HCl \to CuC{l_2} + {H_2}O\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
A{l_2}{O_3} + 6HCl \to 2AlC{l_3} + 3{H_2}O\\
b)\\
HCl + NaOH \to NaCl + {H_2}O\\
Zn + 2NaOH \to N{a_2}Zn{O_2} + {H_2}\\
A{l_2}{O_3} + 2NaOH \to 2NaAl{O_2} + {H_2}O\\
2NaOH + C{O_2} \to N{a_2}C{O_3} + {H_2}O\\
c)\\
CaO + 2HCl \to CaC{l_2} + {H_2}O\\
CaO + C{O_2} \to CaC{O_3}\\
2)\\
a)\\
N{a_2}C{O_3} + {H_2}S{O_4} \to N{a_2}S{O_4} + C{O_2} + {H_2}O\\
{n_{N{a_2}C{O_3}}} = \dfrac{{265 \times 20\% }}{{106}} = 0,5\,mol\\
{n_{{H_2}S{O_4}}} = {n_{N{a_2}C{O_3}}} = 0,5\,mol\\
{C_\% }{H_2}S{O_4} = \dfrac{{0,5 \times 98}}{{200}} \times 100\% = 24,5\% \\
b)\\
{n_{C{O_2}}} = {n_{N{a_2}C{O_3}}} = 0,5\,mol\\
{m_{{\rm{dd}}spu}} = 265 + 200 - 0,5 \times 44 = 443g\\
{n_{N{a_2}S{O_4}}} = {n_{N{a_2}C{O_3}}} = 0,5\,mol\\
{C_\% }N{a_2}S{O_4} = \dfrac{{0,5 \times 142}}{{443}} \times 100\% = 16,03\%
\end{array}\)
