Em tham khảo nha :
\(\begin{array}{l}
1)\\
a)\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
b)\\
{n_{{H_2}}} = \dfrac{{6,72}}{{22,4}} = 0,3mol\\
{n_{FeC{l_2}}} = {n_{{H_2}}} = 0,3mol\\
{m_{FeC{l_2}}} = 0,3 \times 127 = 38,1g\\
2)\\
a)\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
b)\\
{n_{{H_2}}} = \dfrac{{4,48}}{{22,4}} = 0,2mol\\
{n_{ZnC{l_2}}} = {n_{{H_2}}} = 0,2mol\\
{m_{ZnC{l_2}}} = 0,2 \times 136 = 27,2g
\end{array}\)