Câu 2:
a, $Na_2CO_3+ 2CH_3COOH\to 2CH_3COONa+ CO_2+ H_2O$
$n_{CO_2}=\frac{5,6}{22,4}=0,25 mol$
$\Rightarrow n_{Na_2CO_3}=0,25 mol; n_{CH_3COOH}=n_{CH_3COONa}=0,5 mol$
$m_{Na_2CO_3}=0,25.106= 26,5g$
b,
$m_{dd CH_3COOH}=0,5.60:10\%= 300g$
c,
$m_{dd spứ}= 26,5+300-0,25.44= 315,5g$
$\Rightarrow C\%_{CH_3COONa}=\frac{0,5.82.100}{315,5}= 13\%$
Câu 3:
a, $2CH_3COOH+Mg\to (CH_3COO)_2Mg+ H_2$
$n_{Mg}=\frac{2,4}{24}=0,1 mol$
$\Rightarrow n_{CH_3COOH}=0,2 mol; n_{(CH_3COO)_2Mg}= n_{H_2}=0,1 mol$
$C\%_{CH_3COOH}=\frac{0,2.60.100}{200}= 6\%$
b,
$V_{H_2}=0,1.22,4=2,24l$
c,
$m_{dd spứ}= 2,4+200-0,1.2= 202,2g$
$\Rightarrow C\%_{(CH_3COO)_2Mg}=\frac{0,1.142.100}{202,2}= 7\%$