Giải thích các bước giải:
$1.$ $R_{tđ1}=R_1+R_2=30+40=70Ω$
$⇒I=$$\frac{U}{R_{tđ}}=$ $\frac{37,8}{70}=0,54A$
$⇒U_1=R_1.I=30.0,54=16,2V$
$⇒U_2=U-U_1=37,8-16,2=21,6V$
$I_{giảm}=0,54-0,12=0,42A$
$⇒R_{tđ2}=$$\frac{U}{I_{giảm}}=$ $\frac{37,8}{0,42}=90Ω$
$⇒R_3=R_{tđ}-R_1-R_2=90-30-40=20Ω$
$2.$ $R_{tđ}=$$\frac{U}{I}=$ $\frac{5,4}{0,9}=6Ω$
$⇒$$\frac{1}{R_2}=$$\frac{1}{R_{t }}-$$\frac{1}{R_1}=$ $\frac{1}{6}-$ $\frac{1}{10}=$ $\frac{1}{15}$
$⇒R_2=15Ω$
$⇒I=0,9.$$\frac{5}{3}=1,5A$
$⇒I_1=$$\frac{U}{R_1}=$$\frac{5,4}{10}=0,54A$
$⇒I_2=$$\frac{U}{R_2}=$ $\frac{5,4}{15}=0,36A$
$⇒I_3=I-I_1-I_2=1,5-0.54-0.36=0,6A$
$⇒R_3=$$\frac{U}{I_3}=$ $\frac{5,4}{0,6}=9Ω$