$1/$
$n_{Al}=10,8/27=0,4mol$
$2Al+3Cl_2\overset{t^0}\to 2AlCl_3$
Theo pt :
$n_{Cl_2}=3/2.n_{Al}=3/2.0,4=0,6mol$
$⇒V_{Cl_2}=0,6.22,4=13,44l$
$2/$
$n_{H_2}=3,36/22,4=0,15mol$
$Mg+2HCl→MgCl_2+H_2↑$
Theo pt :
$n_{Mg}=n_{H_2}=0,15mol$
$⇒m_{Mg}=0,15.24=3,6g$