\(\begin{array}{l}
1)\\
F{e_2}{O_3} + 3CO \to 2Fe + 3C{O_2}\\
2)\\
4P + 5{O_2} \to 2{P_2}{O_5}\\
a)\\
nP = \dfrac{{6,2}}{{31}} = 0,2\,mol\\
n{O_2} = \dfrac{{6,16}}{{22,4}} = 0,275\,mol\\
\dfrac{{0,2}}{4} < \dfrac{{0,275}}{5}\\
n{O_2}spu = 0,275 - 0,25 = 0,025\,mol\\
m{O_2} = 0,025 \times 32 = 0,8g\\
b)\\
n{P_2}{O_5} = \dfrac{{0,2}}{2} = 0,1\,mol\\
m{P_2}{O_5} = 0,1 \times 142 = 14,2g
\end{array}\)