1)
Phản ứng xảy ra:
\({C_2}{H_4} + 3{O_2}\xrightarrow{{{t^o}}}2C{O_2} + 2{H_2}O\)
Ta có:
\({V_{{O_2}}} = 3{V_{{C_2}{H_4}}} = 11,2.3 = 33,6{\text{ lít}}\)
\( \to {V_{kk}} = 5{V_{{O_2}}} = 33,6.5 = 168{\text{ lít}}\)
2)
Phản ứng xảy ra:
\({C_2}{H_4} + 3{O_2}\xrightarrow{{{t^o}}}2C{O_2} + 2{H_2}O\)
\( \to {V_{{O_2}}} = 3{V_{{C_2}{H_4}}} = 5,6.3 = 16,8{\text{ lít}}\)
\({V_{C{O_2}}} = 2{V_{{C_2}{H_4}}} = 5,6.2 = 11,2{\text{ lít}}\)