a, (x−y)(x2+xy+y2)
=x3+x2y+xy2−x2y−xy2−y3=x3−y3
b, (a3−2a2+a−1)(a−5)
=a4−2a3+a2−a−5a3+10a2−5a+5
=a4−7a3+11a2−6a+5
c, (x2−2x+y2)(x−y)−3xy(y−x)
=x3−2x2+xy2−x2y+2xy−y3−3xy2+3x2y
=x3−2x2−2xy2−2x2y+2xy−y3
Bài 2:
a, (12x−5)(x+1)+(6x−2)(3−2x)=5
⇒12x2+12x−5x−5+18x−12x2−6+4x=5
⇒29x=5+5+6
⇒29x=16⇒x=2916
b, (x−5)(2x+3)−2x(x−3)+x+7=−8
⇒2x2+3x−10x−15−2x2+6x+x+7=−8
⇒0x=−8⇒x∈∅
Chúc bạn học tốt!!!