Đáp án:
\(\begin{array}{l}
{m_1} = 0,438kg\\
{m_2} = 0,226kg
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
V = \frac{m}{D} = \frac{{664}}{{8,3}} = 80c{m^3}\\
{m_1} + {m_2} = m = 0,664(1)\\
{V_1} + {V_2} = V\\
\frac{{{m_1}}}{{{D_1}}} + \frac{{{m_2}}}{{{D_2}}} = \frac{m}{D}\\
\frac{{{m_1}}}{{7300}} + \frac{{{m_2}}}{{11300}} = \frac{{0,664}}{{8300}}(2)\\
{m_1} = 0,438kg\\
{m_2} = 0,226kg
\end{array}\)