Giải thích các bước giải:
$A=2\sqrt{3}+\sqrt{27}-\sqrt{48}+\sqrt{75}$
$=2\sqrt{3}+3\sqrt{3}-4\sqrt{3}+5\sqrt{3}$
$=6\sqrt{3}$
$B=4\sqrt{2}+6\sqrt{\dfrac{1}{2}}-2\dfrac{\sqrt{10}}{\sqrt{5}}$
$=4\sqrt{2}+6\dfrac{\sqrt{2}}{2}-2\sqrt{\dfrac{10}{5}}$
$=4\sqrt{2}+3\sqrt{2}-2\sqrt{2}$
$=5\sqrt{2}$
$C=(\sqrt{6}+\sqrt{2}).\sqrt{(\sqrt{3}-1)^2}$
$=\sqrt{2}(\sqrt{3}+1).(\sqrt{3}-1)$
$=\sqrt{2}(3-1)$
$=2\sqrt{2}$
Học tốt!!!