1/
a.|x-`\frac{1}{3}`|=`\frac{1}{5}`
`TH1`
x-`\frac{1}{3}`=`\frac{1}{5}`
x=`\frac{1}{5}`+ `\frac{1}{3}` =`\frac{8}{15}`
`TH2`
x-`\frac{1}{3}`=-`\frac{1}{5}`
x=-`\frac{1}{5}`+`\frac{1}{3}`=`\frac{2}{15}`
b.x-`\frac{1}{2}`+`\frac{1}{3}`-|-`\frac{1}{7}`|
⇒-`\frac{1}{2}`+`\frac{1}{3}`+`\frac{1}{7}`
=`\frac{-1}{6}`+`\frac{1}{7}`
x=`\frac{-1}{42}`
2/
a.Ta có
`\frac{-53}{54}`=`\frac{1}{54}`-1
`\frac{-54}{55}` =`\frac{1}{55}`-1
`\frac{1}{54}`>`\frac{1}{55}` ⇒`\frac{1}{54}`-1>`\frac{1}{55}`-1
⇒`\frac{-53}{54}`>`\frac{-54}{55}`
b.ta có
`A=` `\frac{10^20+1}{10^21}`=1
`B=` `\frac{10^21+1}{10^22}`=1
`⇒A=B`