`1,` Thay `x=2;y=5` vào `B,` ta có :
`B={3^2(3^5+81^2)}/9^{2.2}`
`={3^2[3^5+(3^4)^2]}/(3^2)^4`
`={3^2[3^5+3^8]}/3^8`
`={3^2. 3^5[3^3+1]}/3^8`
`={3^7.10}/3^8`
`=10/3`
`2,` Vì `x^2≥0` `∀x`
`⇒3x^2≥0`
`⇒A≥199`
Dấu $"="$ xảy ra khi `3x^2=0`
`⇒x^2=0`
`⇒x=0`