`1)`
`a) 27/35 . 12/17 + 27/35 . 5/17 + 8/35`
`= 27/35 . ( 12/17 + 5/17) + 8/35`
`= 27/35 . 1 + 8/35`
`= 27/35 + 8/35`
`= 1`
$\\$
`b) -8/7 . 5/3 + 5/3 . 1/7`
`= (-8/7 + 1/7) . 5/3`
`= (-1) . 5/3`
`= -5/3`
$\\$
`2)`
`a) ( x - 1/3)^2 = 9`
`( x - 1/3)^2 = (+-3)^2`
⇒ `x - 1/3 = 3` hoặc `x - 1/3 = -3`
`x = 3 + 1/3` hoặc `x = -3 + 1/3`
`x = 10/3` hoặc `x = -8/3`
Vậy `x∈ { 10/3 ; -8/3}`