Em tham khảo nha :
\(\begin{array}{l}
1)\\
a)\\
{N_{{O_2}}} = 0,1 \times 6 \times {10^{23}} = 6 \times {10^{22}}\text{(Phân tử )}\\
b)\\
{N_{Zn}} = 0,5 \times 6 \times {10^{23}} = 3 \times {10^{23}}\text{(Nguyên tử )}\\
c)\\
{N_H} = 2 \times 6 \times {10^{23}} = 1,2 \times {10^{24}}\text{(Nguyên tử )}\\
d)\\
{N_{C{O_2}}} = 1,5 \times 6 \times {10^{23}} = 9 \times {10^{23}}\text{(Phân tử )}\\
e)\\
{N_{S{O_2}}} = 0,25 \times 6 \times {10^{23}} = 1,5 \times {10^{23}}\text{(Phân tử )}\\
f)\\
{N_S} = 0,05 \times 6 \times {10^{23}} = 3 \times {10^{22}}\text{(Nguyên tử )}\\
2)\\
a)\\
{n_{Fe}} = \dfrac{{11,2}}{{56}} = 0,2mol\\
b)\\
{n_{C{O_2}}} = \dfrac{{11}}{{44}} = 0,25mol\\
c)\\
{n_{{O_2}}} = \dfrac{{32}}{{32}} = 1mol\\
d)\\
{n_{Mg}} = \dfrac{{9,6}}{{24}} = 0,4mol\\
e)\\
{n_{HCl}} = \dfrac{{18,25}}{{36,5}} = 0,5mol\\
f)\\
{n_{NaOH}} = \dfrac{{80}}{{40}} = 2mol\\
g)\\
{n_{{H_3}P{O_4}}} = \dfrac{{49}}{{98}} = 0,5mol\\
h)\\
{n_{CuS{O_4}}} = \dfrac{{120}}{{160}} = 0,75mol\\
3)\\
a)\\
{m_{Fe}} = 0,05 \times 56 = 1,12g\\
b)\\
{m_{{H_2}}} = 1,5 \times 2 = 3g\\
c)\\
{m_{{H_2}S{O_4}}} = 0,5 \times 98 = 49g\\
d)\\
{m_{Cu{{(OH)}_2}}} = 0,2 \times 9819,6g\\
e)\\
{n_{Ca{{(HC{O_3})}_2}}} = 0,115 \times 162 = 18,63g\\
f)\\
{m_{KMn{O_4}}} = 0,075 \times 158 = 11,85g
\end{array}\)