1)
Phản ứng xảy ra:
\(C{H_3}COOH + KOH\xrightarrow{{}}C{H_3}COOK + {H_2}O\)
Ta có:
\({n_{KOH}} = 0,2.0,35 = 0,07{\text{ mol = }}{{\text{n}}_{C{H_3}COOH}} = {n_{C{H_3}COOK}}\)
\( \to {C_{M{\text{ C}}{{\text{H}}_3}COOH}} = \frac{{0,07}}{{0,12}} = 0,583M\)
\({V_{dd}} = 200 + 120 = 320{\text{ ml = 0}}{\text{,32 lít}}\)
\( \to {C_{M{\text{ C}}{{\text{H}}_3}COONa}} = \frac{{0,07}}{{0,32}} = 0,21875M\)
2)
Phản ứng xảy ra:
\(2C{H_3}COOH + F{\text{e}}\xrightarrow{{}}{(C{H_3}COO)_2}Fe + {H_2}\)
\({n_{Fe}} = \frac{{11,2}}{{56}} = 0,2{\text{ mol = }}{{\text{n}}_{{H_2}}} = {n_{{{(C{H_3}COO)}_2}Fe}}\)
\({n_{C{H_3}COOH}} = 2{n_{Fe}} = 0,4{\text{ mol}}\)
\( \to {V_{C{H_3}COOH}} = \frac{{0,4}}{2} = 0,2{\text{ lít}}\)
\({V_{{H_2}}} = 0,2.22,4 = 4,48{\text{ lít}}\)
\( \to {C_{M{\text{ (C}}{{\text{H}}_3}COO{)_2}Fe}} = \frac{{0,2}}{{0,2}} = 1M\)