Đáp án:
a, \(\begin{array}{*{20}{l}}
{n{C_6}{H_5}CHC{H_2}}& \to &{\left( { - CH\left( {{C_6}{H_5}} \right) - C{H_2} - } \right)n}
\end{array}\)
b, \(\begin{array}{*{20}{l}}
{B{r_2}}& + &{{C_6}{H_5}CHC{H_2}}& \to &{{C_6}{H_5} - CH\left( {Br} \right) - C{H_2}Br}
\end{array}\)
c, \(\begin{array}{*{20}{l}}
{HCl}& + &{{C_6}{H_5}CHC{H_2}}& \to &{{C_6}{H_5} - CHCl - C{H_3}}
\end{array}\)