1/
ax - bx - cx + dx
=x.(a-b-c+d)
2/
a, Ta có : (a - b + c) - (a + c )
= a - b + c - a - c
=(a-a)+(c-c)-b
=0-0-b
=-b
⇒ (a - b + c) - (a + c ) = -b
b, Ta có : (a + b) - (b - a) + c
=a + b - b + a + c
=(a+a)+(b-b)+c
=2a+0+c
=2a+c
⇒(a + b) - (b - a) + c =2a+c
c, Ta có : - (a + b - c) + (a - b - c)
= -a-b+c+a-b-c
=(-a+a)-(b+b)+(c-c)
=0-2b+0
=-2b
⇒ - (a + b - c) + (a - b - c) = -2b
d, Ta có : a( b + c ) - a( b + d )
=ab+ac-ab-ad
=(ab-ab)+(ac-ad)
=ac-ad
=a(c-d)
⇒a( b + c ) - a( b + d ) = a( c - d)
e, Ta có : a(b - c) + a( d + c )
=ab-ac+ad+ac
=(ab+ad)+(ac-ac)
=ab+ad
=a(b+d)
⇒ a(b - c) + a( d + c ) = a( b + d )