Giải thích các bước giải:
Bài `1:`
`10x^2-29x+10`
`=10x^2-4x-25x+10`
`=2x.(5x-2)-5.(5x-2)`
`=(2x-5).(5x-2)`
Bài `2:`
`a)` `3x^2-2x-1=0`
`<=> 3x^2-3x+x-1=0`
`<=> 3x.(x-1)+(x-1)=0`
`<=> (3x+1).(x-1)=0`
`<=>`\(\left[ \begin{array}{l}3x+1=0\\x-1=0\end{array} \right.\) `<=>` \(\left[ \begin{array}{l}x=-\dfrac{1}{3}\\x=1\end{array} \right.\)
Vậy `x in {-1/3;1}`
`b)` `x^2-x=6`
`<=> x^2-x-6=0`
`<=> x^2+2x-3x-6=0`
`<=> x.(x+2)-3.(x+2)=0`
`<=> (x-3).(x+2)=0`
`<=>` \(\left[ \begin{array}{l}x-3=0\\x+2=0\end{array} \right.\) `<=>` \(\left[ \begin{array}{l}x=3\\x=-2\end{array} \right.\)
Vậy `x in {-2;3}`