Đáp án đúng: B
Giải chi tiết:\(\begin{array}{l}\,12 + 8.{\left( {\frac{{ - 1}}{2}} \right)^3} + {\left[ {{{\left( { - 2018} \right)}^0}:\frac{1}{2}} \right]^2}\\ = 12 + 8.\frac{{ - 1}}{8} + {\left[ {1:\frac{1}{2}} \right]^2}\\ = 12 - 1\,\,\,\,\,\,\,\,\,\, + \,\,\,\,\,{2^2}\\ = \,\,\,\,\,\,11\,\,\,\,\,\,\,\,\,\,\,\, + 4\\ = \,\,\,\,\,\,15\end{array}\)
Chọn B