Ta có: |13x - 4|=|2x +1|
⇔ \(\left[ \begin{array}{l}13x-4=2x+1\\13x-4=-2x-1\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}13x-2x=1+4\\13x+2x=-1+4\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}11x=5\\15x=3\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=\frac{5}{11} \\x=\frac{1}{5} \end{array} \right.\)
Vậy.........
