Giải thích các bước giải:
\[\frac{{{{17}^{250}}{{.20}^{38}}}}{{{{17}^{248}}{{.25}^{20}}{{.4}^{38}}}} = \frac{{{{17}^{248}}{{.17}^2}.{{\left( {4.5} \right)}^{38}}}}{{{{17}^{248}}.{{\left( {{5^2}} \right)}^{20}}{{.4}^{38}}}} = \frac{{{{17}^2}{{.4}^{38}}{{.5}^{38}}}}{{{5^{40}}{{.4}^{38}}}} = \frac{{{{17}^2}}}{{{5^2}}} = {\left( {\frac{{17}}{5}} \right)^2}\]