`|2x-1/3| +5/6 =1`
`-> |2x-1/3| = 1 -5/6`
`-> |2x-1/3| = 6/6 -5/6`
`-> |2x -1/3| =1/6`
`-> 2x - 1/3 =1/6` hoặc `2x -1/3 =-1/6`
Xét `2x -1/3 =1/6`
`-> 2x = 1/6 +1/3`
`-> 2x = 1/6 + 2/6`
`-> 2x = 3/6`
`-> 2x = 1/2`
`-> x = 1/2 : 2 = 1/2 . 1/2`
`-> x = 1/4`
Xét `2x -1/3 =-1/6`
`-> 2x = -1/6 +1/3`
`-> 2x = -1/6 + 2/6`
`-> 2x = 1/6`
`-> x = 1/6 :2`
`-> x = 1/12`
Vậy `x \in {1/4 ;1/12}`