`|x|\times |x/(x+2)|=1`
`⇔|x^2/(x+2)|=1`
\(⇔\left[ \begin{array}{l}\dfrac{x^2}{x+2}=1\\\dfrac{x^2}{x+2}=-1\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x^2-x-2=0\\x^2+x+2=0\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=-1; 2\\x∈∅\end{array} \right.\)
Vậy `x=-1; 2`
