Đáp án: $3$.
Giải thích các bước giải:
$\dfrac{2^{10} . 2^{13} + 2^{21} . 20}{2^{24}}$
$= \dfrac{2^{23} + 2^{21} . 2^2 . 5}{2^{24}}$
$= \dfrac{2^{23} + 2^{23} . 5}{2^{24}}$
$= \dfrac{2^{23}. (1 + 5)}{2^{24}}$
$= \dfrac{2^{23} . 6}{2^{24}}$
$= \dfrac{2^{24} . 3}{2^{24}}$
$= 3$.