Đáp án đúng: B
Giải chi tiết:\(\begin{array}{l}\,\,\,\,\,\,\,\,{2^x}{.16^2} = 1024\\\,\,\,\,{2^x}.{\left( {{2^4}} \right)^2} = {2^{10}}\\\,\,\,\,\,\,{2^x}{.2^8}\,\,\,\,\,\,\, = {2^{10}}\\\,\,\,\,\,\,{2^x}\,\,\,\,\,\,\,\,\,\,\,\,\, = {2^{10 - 8}}\\\,\,\,\,\,\,{2^x}\,\,\,\,\,\,\,\,\,\,\,\,\, = {2^2}\\\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 2.\,\,\,\,\,\,\end{array}\)
Vậy \(x = 2.\)
Chọn B.