ĐKXĐ: $x \neq ±1$
$\frac{2x}{x^2-1}$ + $\frac{x-1}{2x+2}$
= $\frac{2x}{(x-1)(x+1)}$ + $\frac{x-1}{2(x+1)}$
= $\frac{2x.2}{2(x-1)(x+1)}$ + $\frac{(x-1)^2}{2(x-1)(x+1)}$
= $\frac{4x+x^2-2x+1}{2(x-1)(x+1)}$
= $\frac{x^2+2x+1}{2(x-1)(x+1)}$
= $\frac{(x+1)^2}{2(x-1)(x+1)}$
= $\frac{x+1}{2(x-1)}$
