Gửi bạn nhé !
Đặt : $B=2+2^2+2^3+...+2^{50} $
$⇒2B = 2^2+2^3+2^4 + ...+2^{51}$
$⇒2B-B=(2^2+2^3+2^4+..+2^{51})-(2+2^2+2^3+...+2^{50}) $
$⇒B=2^{51}-2$
Do đó : $2+2^2+2^3+...+2^{50}-2^{51}+5$
$=2^{51}-2+2^{51}+5 = 3 $
Vậy : $2+2^2+2^3+...+2^{50}-2^{51}+5 = 3$.