`2^x + 2^( x + 2 ) = 8`
`⇔ 2^x . 1 + 2^x . 2^2 = 8`
`⇔ 2^x . ( 1 + 2^2 ) = 8`
`⇔ 2^x . 5 = 8`
`⇔ 2^x = 8 : 5`
`⇔ 2^x = 8/5 (` Vô lý `)`
`⇒ x ∈ ∅`
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`2^x + 2^x + 2 = 8`
`⇔ 2^x . 2 = 8 - 2`
`⇔ 2^( x + 1 ) = 6 (` Vô lý `)`
`⇒ x ∈ ∅`