`2(3x-1)(2x+5)-6(2x-1)(x+2) = -6`
`⇔ 12x^2 + 26x - 10 - 6(2x-1)(x+2) = -6`
`⇔ 12x^2 + 26x - 10 - 12x^2 - 18x + 12 = -6`
`⇔ 8x + 2 = -6`
`⇔ 8x = -8`
`⇔ x = -1`
Vậy `S ={-1}`
Đáp án:
Giải thích các bước giải:
$12x^2 + 26x - 10 - 6(2x-1)(x+2) = -6$
$12x^2 + 26x - 10 - 12x^2 - 18x + 12 = -6$
$8x + 2 = -6$
$8x = -8$
$x = -1$
$Vậy S ={-1}$
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