Đáp án:
$\begin{array}{l}
\left( {2x + 3} \right)\left( {3 - 2x} \right) - {\left( {2x - 1} \right)^2}\\
= - \left( {2x + 3} \right)\left( {2x - 3} \right) - \left( {4{x^2} - 4x + 1} \right)\\
= - \left( {4{x^2} - 9} \right) - 4{x^2} + 4x - 1\\
= - 4{x^2} + 9 - 4{x^2} + 4x - 1\\
= 4x + 8
\end{array}$