Đáp án:
$\text{ $\dfrac{x^2+6x-16}{x-2}$ = x + 8 }$
$\text{ĐKXĐ : x $\neq$ 2}$
$\text{<=> $\dfrac{x^2+6x-16}{x-2}$ = $\dfrac{(x+8)(x-2)}{x-2}$ }$
$\text{=>x² + 6x -16 = (x+8)(x-2)}$
$\text{<=> x²+6x-16 = x²-2x+8x-16 }$
$\text{<=> x² - x² + 6x+2x-8x = -16+16 }$
$\text{<=> 0x = 0 }$
$\text{<=>x vô số nghiệm }$