Ta có :$\frac{x+2}{98}+1 + \frac{x+3}{97} +1= \frac{x+4}{96} +1+ \frac{x+5}{95}+1$
$⇔\frac{x+100}{98} + \frac{x+100}{97} = \frac{x+100}{96} + \frac{x+100}{95}$
$⇔(x+100).(\frac{1}{98} + \frac{1}{97} - \frac{1}{96} - \frac{1}{95})=0$
$⇔ x+100=0$
( Do$ \frac{1}{98} + \frac{1}{97} - \frac{1}{96} - \frac{1}{95} < 0 $ )
$⇔x=-100$
Vậy : $x=-100$
Chúc bạn học tốt !
